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You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts, and the final equilibrium temperature of the two substances is 0.00∘C. What was the initial temperature of the copper cube? Assume no heat is exchanged with the surroundings.

Respuesta :

Answer:

[tex]T = 29.66 ^o C[/tex]

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

[tex]ms \Delta T = m' L[/tex]

so here we have

[tex]0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)[/tex]

[tex]T = \frac{2512.5}{0.220 \times 385}[/tex]

[tex]T = 29.66 ^o C[/tex]

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