What is the area of a rectangle with side lengths of 68 meter and 410 meter?

Enter your answer as a fraction in simplest form.

Respuesta :

Area of a rectangle with side lengths of 68 meter and 410 meter is 27880 square feet

Solution:

Given that rectangle with side lengths of 68 meter and 410 meter

To find: area of rectangle

The area of rectangle can be calculated by multiplying length and width of rectangle

The area of rectangle is given as:

[tex]\text {area of rectangle }=\text { length } \times \text { width }[/tex]

Substitute the given values length = 68 meter and width = 410 meter

[tex]\text {area of rectangle}=68 \times 410[/tex]

On solving we get,

Area of rectangle = 27880 square feet

Thus the area of a rectangle is obtained as 27880 square feet