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The protons of an organic compound produce a signal at 2.1 ppm in a 1H NMR spectrum obtained using a 60-MHz spectrometer. When the same sample is placed in a 300-MHz spectrometer, where does the signal appear?

Respuesta :

codedmog101

Answer:

2.1ppm

Explanation:

Nuclear magnetic resonance spectroscopy,NMR is use to measure local magnetic field around atomic nuclei. Nuclear Magnetic Resonance Spectroscopy,NMR is used to identify organic compounds. It gives details about organic compound structures. Also, Nuclear, Magnetic Resonance Spectroscopy, NMR is used by biochemists to discover the structure of proteins and other complex structures.

In order to calculate parts per million, ppm, we use the formula below.

Ppm= frequency (in hertz)/ MHZ

The signal at 2.1 ppm in a 1H NMR spectrum obtained using a 60-MHz spectrometer will still be the signal When the same sample is placed in a 300-MHz spectrometer, only the RESOLUTION will change.

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