Answer:
Final velocity, v = 0.28 m/s
Explanation:
Given that,
Mass of the model, [tex]m_1=0.205\ kg[/tex]
Speed of the model, [tex]u_1=0.72\ m/s[/tex]
Mass of another model, [tex]m_2=0.32\ kg[/tex]
Initial speed of another model, [tex]u_2=0[/tex]
To find,
Final velocity
Solution,
Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]
[tex]V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}[/tex]
[tex]V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}[/tex]
V = 0.28 m/s
So, their final velocity is 0.28 m/s. Hence, this is the required solution.
