Answer:
(0.1533, 0.8932)
Step-by-step explanation:
given that in a survey of 1011 adults, a polling agency asked, "When you retire, do you think you will have enough money to live comfortably or not.
Sample size = number of persons surveyed = n = 1011
X = persons who stated that they were worried about having enough money to live comfortably in retirement=529
Sample proportion p = [tex]\frac{x}{n} =0.5232[/tex]
[tex]q=1-p = 0.4768[/tex]
Std error = [tex]=\sqrt{\frac{pq}{n} } \\=0.1439[/tex]
Margin of error for 99% = ±2.58*std error
= 0.3699
Confidence interval
= p±Marginof error
= [tex](0.1533, 0.8932)[/tex]
