Answer:
[tex]g' = g = 9.81 m/s^2[/tex]
so gravity will be same as that of surface of earth
Explanation:
As we know that the acceleration due to gravity is given as
[tex]g = \frac{GM}{R^2}[/tex]
here we have
[tex]M = 4M_e[/tex]
[tex]R = 2R_e[/tex]
we know that for earth we have
[tex]g = 9.81 = \frac{GM_e}{R_e^2}[/tex]
now if the radius and mass is given as above
[tex]g' = \frac{G(4M_e)}{(2R_e)^2}[/tex]
[tex]g' = \frac{GM_e}{R_e^2}[/tex]
[tex]g' = g = 9.81 m/s^2[/tex]
so gravity will be same as that of surface of earth
