Answer:
17.08984375
Explanation:
A = Area
L = Thickness of material
[tex]k_a[/tex] = Electrical conductivity of air = 0.0256
[tex]k_s[/tex] = Electrical conductivity of Styrofoam = 0.01
Conductance is given by
[tex]G=\frac{k A}{l}[/tex]
For Styrofoam
[tex]G_s=\frac{k_sA}{l}\\\Rightarrow G_s=\frac{0.01\times A}{0.08}[/tex]
For air
[tex]G_a=\frac{k_aA}{l}\\\Rightarrow G_a=\frac{0.0256\times A}{0.0035}[/tex]
Dividing the two equations
[tex]\frac{G_s}{G_a}=\frac{\frac{0.01\times A}{0.08}}{\frac{0.0256\times A}{3.5}}\\\Rightarrow \frac{G_s}{G_a}=17.08984375[/tex]
The body can adjust up to a factor of 17.08984375