Respuesta :
Answer:
[tex]P_{i}[/tex] = 2.97 atm
Explanation:
The work in thermodynamic processes has several expressions, in the case of isothermal processes the work is
W = n RT ln ( [tex]V_{i}[/tex] / [tex]V_{f}[/tex])
Where R is the constant of the ideal gases with a value of 8.314 J / mol K and T the absolute temperature
Let's look for the volume ratio
T = 26.4 +273.15 = 299.55k
Ln ( [tex]V_{i}[/tex] / [tex]V_{f}[/tex])
= W / n RT
Ln( [tex]V_{i}[/tex] / [tex]V_{f}[/tex])
= 383 / (0.332 8.314 299.55)
Ln( [tex]V_{i}[/tex] / [tex]V_{f}[/tex])
= 0.4632
( [tex]V_{i}[/tex] / [tex]V_{f}[/tex]) = e 0.4632
( [tex]V_{i}[/tex] / [tex]V_{f}[/tex]) = 1,589
Let's use the ideal gas equation for two volumes
[tex]P_{i} V_{i}[/tex] = n R T
[tex]P_{i} V_{i}[/tex] = n RT
The temperature is the same because it is an isothermal process, this equation is the same
[tex]P_{i} V_{i}[/tex] = [tex]P_{f} V_{f}[/tex]
Vi / Vf = [tex]P_{f}/P_{i}[/tex]
[tex]P_{i}[/tex]= [tex]P_{f}[/tex] [tex]V_{i}[/tex] / [tex]V_{f}[/tex]
[tex]P_{i}[/tex] = 1.87 1,589
[tex]P_{i}[/tex] = 2.97 atm
