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A basketball is pressurized to a gauge pressure of PG = 65 kPa when at the surface of a swimming pool. (Patm = 101 kPa). The ball is then submerged in the pool of water which has a density rho = 1000 kg/m3. Assume the ball does not change in mass, temperature, or volume as it is submerged.

Respuesta :

Answer:

[tex]P_{abs} =166\ kPa[/tex]

Explanation:

given,

Gauge pressure = 65 kPa

atmospheric pressure = 101 kPa

density of water = 1000 Kg/m³

Absolute pressure inside basketball = ?

[tex]P_{abs} = P_{gauge} + P_{atm}[/tex]

[tex]P_{abs} =65\ kPa+ 101\ kPa[/tex]

[tex]P_{abs} =166\ kPa[/tex]

Absolute pressure inside the basketball when it is submerged in water is equal to  [tex]P_{abs} =166\ kPa[/tex]

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