Answer:
The length of segment EF is 2 units
Step-by-step explanation:
we know that
The formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex]E(7,-2), F(7,-4)[/tex]
substitute in the formula
[tex]EF=\sqrt{(-4+2)^{2}+(7-7)^{2}}[/tex]
[tex]EF=\sqrt{(-2)^{2}+(0)^{2}}[/tex]
[tex]EF=\sqrt{4}\ units[/tex]
[tex]EF=2\ units[/tex]
