Answer:
The probability that no one in a family of five will be hospitalized in a year is 0,2373
Step-by-step explanation:
Let p denote the probability of being hospitalized during a year,
Then p=0.25
And p' the probability of not being hospitalized during a year is 1-p
Thus p' = 1-p = 1-0.25 = 0.75
The probability that no one in a family of five will be hospitalized in a year is equal to [tex]p'^{5}[/tex]. That is
[tex]p'^{5}[/tex] = [tex]0.75^{5}[/tex] ≈ 0,2373
