Answer:
2. addition of more tin metal to the anode compartment
Explanation:
For the given cell reaction:
Hydrogen is undergoing reduction
Sn is undergoing oxidation
The cell potential of a cell depends upon
a) the temperature
b) the concentration of aqueous species
c) the pressure of gaseous species
It is independent of the amount of the solid present or taken
The dependence of cell potential on concentration and temperature is given in the form of Nernst's equation:
[tex]E_{cell{=E^{0}_{cell}-\frac{RT}{nF}log(\frac{anode]}{[cathode]} )[/tex]
Where
n = number of electrons
T = temperature
F= Faraday;s constant
R= gas constant
For given cell reaction the equation will be:
[tex]E_{cell{=E^{0}_{cell}-\frac{RT}{2XF}log(\frac{[Sn^{+2}][P_{H2}]}{[H^{+}]^{2}} )[/tex]
Thus the action that would not change the measured cell potential would be: 2. addition of more tin metal to the anode compartment