Answer:
Part a)
[tex]n = 858.5 moles[/tex]
Part b)
[tex]w = 27.47 kg[/tex]
Explanation:
Volume of the cylindrical container is given as
[tex]V = \pi r^2 L[/tex]
now we have
[tex]V = \pi(\frac{0.91}{2})^2(1.50)[/tex]
[tex]V = 0.97 m^3[/tex]
pressure of the gas is given as
[tex]P = 21.7 atm[/tex]
[tex]P = 21.7 \times 1.01 \times 10^5 [/tex]
[tex]P = 2.19 \times 10^6 Pa[/tex]
Now we have
[tex]PV = nRT[/tex]
[tex](2.19 \times 10^6)(0.97) = n(8.31)(273 + 25)[/tex]
[tex]n = 858.5 moles[/tex]
Part b)
Mass of the container is increased as the mass of the gas
[tex]\frac{w}{M} = 858.5[/tex]
[tex]\frac{w}{0.032} = 858.5[/tex]
[tex]w = 27.47 kg[/tex]