Answer:
[tex]$ \frac{1}{45} $[/tex]
Step-by-step explanation:
There are 10 balls. They are placed in a bag. So, the number of sample space, n(S) = 10.
Now, the probability of drawing the first yellow ball = [tex]$ \frac{No. \hspace{2mm} of \hspace{2mm} yellow \hspace{2mm} balls}{Total \hspace{2mm} No. \hspace{2mm} of \hspace{2mm} balls} $[/tex].
Probability of drawing first ball = [tex]$ \frac{2}{10} $[/tex]
Now, another yellow ball is to be drawn without replacing the first ball drawn.
Therefore, the number f total balls now becomes 9 and the number of yellow balls become 1.
Hence, the probability becomes [tex]$ \frac{1}{9} $[/tex]
The total probability becomes [tex]$ \frac{2}{10} \times \frac{1}{9} $[/tex] = [tex]$ \frac{1}{45} $[/tex].
