Answer:
Option C. [tex]y=5x-1[/tex]
Step-by-step explanation:
step 1
Find the slope of the linear equation
take two points from the graph
(0,-1) and (1,4)
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
substitute the values
[tex]m=\frac{4+11}{1-0}[/tex]
[tex]m=\frac{51}{1}[/tex]
[tex]m=5[/tex]
step 2
Find the linear equation in slope intercept form
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-intercept
we have
[tex]m=5[/tex]
[tex]b=-1[/tex] ----> the y-intercept is the point (0,-1)
substitute
[tex]y=5x-1[/tex]
