Respuesta :
Answer:
Rotational inertia of the object is, [tex]I=0.023\ kg-m^2[/tex]
Explanation:
Given that,
Mass of the object, m = 20 kg
Torsion constant of the wire, K = 0.85 N-m
Number of cycles, n = 69
Time, t = 66 s
To find,
The rotational inertia of the object.
Solution,
There exists a relationship between the moment of inertia, time period and the torsion constant of the spring is given by :
[tex]T=2\pi\sqrt{\dfrac{I}{K}}[/tex]
Here I is the moment of inertia
T is the time period, and it is equal to the number of cycles per unit time
[tex]I=\dfrac{T^2K}{4\pi ^2}[/tex]
[tex]I=\dfrac{(69/66)^2\times 0.85}{4\pi ^2}[/tex]
[tex]I=0.023\ kg-m^2[/tex]
So, the rotational inertia of the object is [tex]0.023\ kg-m^2[/tex].
