Answer:
Fred can play maximum of 7 games.
Step-by-step explanation:
Money had with Fred = $20
Cost for each game = $2
Fred needs to leave the arcade with $5.00 to pay for lunch.
Money left with Fred = $20 - $5.00 = $15
Let the number of games be x.
Hence Number of games Fred can play can be calculated as;
Cost for each game multiplied number of games should be less than or equal to Money left with Fred
Hence equation can be framed as;
[tex]2x\leq 15\\\\x\leq \frac{15}{2}\\\\x\leq 7.5[/tex]
From above we can say number of games fred can play is 7.5 but number of games cannot be in point hence maximum of 7 games he can play.
Hence Fred can play maximum of 7 games.
