Answer:
The following reaction will occur at cathode:
[tex]Ni^{+2}(aq)+2e--->Ni(s)[/tex]
Explanation:
The two half reaction during electrolysis of aqueous nickel sulfate will be
a) anode reaction :
Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:
[tex]2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e[/tex]
b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:
[tex]Ni^{+2}(aq)+2e--->Ni(s)[/tex]
Thus the overall reaction will be:
[tex]2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)[/tex]
