Answer:
[tex]x=\frac{log 3.2}{5*log21}[/tex]
Step-by-step explanation:
In this type of question, first we have to make sure that the variable that we need to find comes out of the exponential part by applying logarithms
Given, [tex]5[/tex]·[tex]21^{5x}=16[/tex]
Step1: Dividing by 5 on both sides we get, [tex]21^{5x}=\frac{16}{5}[/tex]
⇒[tex]21^{5x}=3.2[/tex]
Step2: Applying logarithm on both sides, [tex]5x*log21=log3.2[/tex]
Step3: Divide by [tex]5[/tex]㏒[tex]21[/tex] , [tex]x=\frac{log 3.2}{5*log21}[/tex]
therefore, [tex]5[/tex]·[tex]21^{5x}=16[/tex]
⇒[tex]21^{5x}=3.2[/tex]
⇒[tex]5x*log21=log3.2[/tex]
⇒[tex]x=\frac{log 3.2}{5*log21}[/tex]
