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A uniform crate with a massof 30 kg must be moved up along the 15° incline without tipping. Knowing that force P is horizontal, determine (a) the largest allowable coefficient of static friction between the crate and the incline, (b) the corresponding magnitude of force P.

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Answer:

coefficient of friction =0.268

magnitude of force P=289.78N

Explanation:

The coefficient of friction is obtained by mgsinФ/mgcosФ=tanФ=tan15=0.268

force P is horizontal as stated in the question, horizontal component of P=mgcosФ=30*10*cos15=289.78

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