Answer:
the high temperature needed to operate this refrigerator is C) 137.4° C
Explanation:
Hello!
The carnot refrigeration cycle is one in which a machine absorbs heat from an enclosure and expels it to the surroundings, the equation that defines the COP performance coefficient for this cycle is:
[tex]COP=\frac{T1}{T2-T1}[/tex]
COP=performance coefficient =2.1
T1= Low temperature
T2=high temperature
Now use algebra to find the high temperature
[tex]COP=\frac{T1}{T2-T1}\\(T2-T1)=\frac{T1}{COP}\\T2=\frac{T1}{COP}+T1\\T2=T1(\frac{1}{COP} +1)[/tex]
If we replace the values:
note = remember that the temperature must be in absolute units, for which we must add 273.15 to the low temperature to find the temperature in Kelvin
T1 = 5 + 273.15 = 278.15K
[tex]T2=278.15(\frac{1}{2.1} +1)=410.60k[/tex]
In celsius
T2=410.60-273.15=137.4° C
the high temperature needed to operate this refrigerator is C) 137.4° C
