Answer:
1.147 %
Explanation:
[tex]\rho[/tex] = Density of mercury = [tex]1.36\times 10^4\ kg/m^3[/tex]
g = Acceleration due to gravity = 9.81 m/s²
h = Height of mercury = 8.69 m
Standard atmospheric pressure = [tex]1.01\times 10^5\ Pa[/tex]
6.55 mmHg converting to Pa
[tex]\rho gh\\ =1.36\times 10^4\times 9.81\times 8.69\times 10^{-3}\\ =1159.38504\ Pa[/tex]
Dividing air pressure by the above value
[tex]\frac{1159.38504}{1.01\times 10^5}\times 100=1.147\ \%[/tex]
The fraction of atmospheric pressure is 1.147 %