Kristin bought 2 fancy shirts and 5 plain shirts.
Step-by-step explanation:
Amount spent on shirts = $131
Cost of one fancy shirt = $28
Cost of one plain shirt = $15
Shirts bought = 7
Let,
x be the number of fancy shirts bought
y be the number of plain shirts bought
According to given statement;
x+y=7 Eqn 1
28x+15y=131 Eqn 2
From Eqn 1
[tex]x=7-y[/tex]
Putting this value of x in Eqn 2
[tex]28(7-y)+15y=131\\196-28y+15y=131\\-13y=131-196\\-13y=-65[/tex]
Dividing both sides by -13
[tex]\frac{-13y}{-13}=\frac{-65}{-13}\\y=5[/tex]
Putting y=5 in Eqn 1
[tex]x+5=7\\x=7-5\\x=2[/tex]
Kristin bought 2 fancy shirts and 5 plain shirts.
Keywords: linear equation, substitution method
Learn more about linear equations at:
#LearnwithBrainly
The number of plain shirts bought is 5 and number of fancy shirts bought is 2
Let number of plain shirts bought be "a"
Let number of fancy shirts bought be "b"
Given that Kristin bought seven total shirts
plain shirts bought + fancy shirts bought = 7
a + b = 7 ----- eqn 1
Also that Kristin spent $131 on shirts and Fancy shirts cost $28 and plain shirts cost $15
15a + 28b = 131 ---- eqn 2
Multiply first equation by 28 to eliminate b:
28a + 28b = 196 ---- eqn 3
subtracting eqn 2 from eqn 3
28a + 28b = 196
15a + 28b = 131
(-) ------------------
13a = 65
a = 5
Substitute a = 5 in eqn 2
15(5) + 28b = 131
75 + 28b = 131
28b = 56
b = 2
Thus the number of plain shirts bought is 5 and number of fancy shirts bought is 2
