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An ideal incompressible fluid flows at 12 m/s in a horizontal pipe. If the pipe widens to twice its original radius, what is the flow speed in the wider section?
a) 4 m/sb) 6 m/sc) 12 m/sd) 3 m/s

Respuesta :

Answer:

d) 3 m/s

Explanation:

As we know by equation of continuity

[tex]A_1v_1 = A_2v_2[/tex]

here we have

[tex]A_1 = \pi r^2[/tex]

[tex]A_2 = \pi (2r)^2[/tex]

[tex]A_2 = 4\pi r^2[/tex]

now from above equation we have

[tex]\pi r^2 v_1 = 4\pi r^2 v_2[/tex]

[tex]v_2 = \frac{v_1}{4}[/tex]

here we have

[tex]v_1 = 12 m/s[/tex]

[tex]v_2 = 3 m/s[/tex]

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