The spring constant is 1.15 × 10⁶. Then the frequency of the car and passenger is 3.25 Hertz.
To and Fro motion of a body is called vibration.
A 78 kg person steps into a car of mass 2667 kg, causing it to sink 2.35 cm on its springs.
The spring force is given as
[tex]\rm k = \dfrac{F}{x}\\\\\\k = \dfrac{(2667+78)*9.81}{2.35*10^{-2}}\\\\\\k = 1.15*10^{-6}[/tex]
Then the frequency of vibration or oscillation will be
[tex]f = \dfrac{1}{2\pi} \sqrt{\dfrac{k}{m}}\\\\\\f = \dfrac{1}{2\pi} \sqrt{\dfrac{1.15*10^6}{2667+78}}\\\\\\f = 3.25 \ Hz[/tex]
More about the vibration link is given below.
https://brainly.com/question/732018
