Answer:
0.04247,6
Step-by-step explanation:
Given that a biased coin has a 0.6 chance of coming up heads when flipped
X no of coins which showed head is binomial with p = 0.6 since each trial is independent of the other
When there are 10 flips we have n =10
This gives
probability of flipping 3 or fewer heads in 10 flips.
=[tex]P(X=3)\\=10C3 (0.6)^3 (0.4)^7\\= 0.04247[/tex]
Expected number of heads in 10 flips
E(x)
=[tex]np = 6[/tex]
