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During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small- business owners. It shows that 65 percent of small-business owners do not approve of the changes. Develop a 95 percent confidence interval for the proportion opposing health care changes. Comment on the result

Respuesta :

Answer:

(0.6188, 0.6812)

Step-by-step explanation:

Given that during a national debate on changes to health care, a cable news service performs an opinion poll of 500 small- business owners.

Persons who do not approve of the change = 65%

p = 0.65

n = 500

q=0.35

Std error = [tex]\sqrt{0.65*0.35/500} \\=0.0159[/tex]

Margin of error for 95% = 1.96 * std error

= 0.0312

Confidence interval = p±Margin of error

= [tex](0.65-0.0312, 0.65+0.0312)\\=(0.6188, 0.6812)[/tex]

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