Respuesta :
Answer:
1/100
Step-by-step explanation:
The number of total possible outcomes is 10(we have ten balls)
let, P(O) be the probability of choosing a ball that is numbered O
P(1) be the probability of choosing a ball that is numbered 1
P(2) be the probability of choosing a ball that is numbered 2
P(3) be the probability of choosing a ball that is numbered 3
P(4) be the probability of choosing a ball that is numbered 4
P(5) be the probability of choosing a ball that is numbered 5
since probability = number of favorable outcome / number of total possible outcome
The favorable outcome for balls that are number 0 is 5, making P(O)= 5/10
The favorable outcome for balls that are number 1 is 1, making P(1)= 1/10
The favorable outcome for balls that are number 2 is 1, making P(2)= 1/10
The favorable outcome for balls that are number 3 is 1, making P(3)= 1/10
The favorable outcome for balls that are number 4 is 1, making P(4)= 1/10
The favorable outcome for balls that are number 5 is 1, making P(5)= 1/10
Three balls are randomly chosen with replacement, to find the probability of choosing three balls whose sum will make 10, we have to consider the possible combination of the sum of three numbers that could result to 10
we have :
0+5+5(since the balls were chosen with replacement ,we can pick two balls numbered 5 and a ball numbered 0)
1+4+5
2+3+5
2+4+4
3+3+4
Hence the probability will be given as ;
[p(0)×P(5)×P(5)] + [P(1)×P(4)×P(5)] + [P(2)×P(3)×P(5)] + [P(2)×P(4)×P(4)] + [P(3)×P(3)×P(4)] =
(1/2×1/10×1/10) + (1/10×1/10×1/10) + (1/10×1/10×1/10) + (1/10×1/10×1/10) + (1/10×1/10×1/10) = 1/100
Answer:
33/1000
Step-by-step explanation:
Count the case to get 10
5,5,0= 16
4,4,2=3
5,2,3=6
5,4,1=6
4,3,3=3
15+6+6+3+3= 33 then 33/1000 will be our answer
