Answer:
10^6 Pa
Explanation:
Radius of the opening, r = 0.491 mm = 0.491 x 10^-3 m
Force, F = 0.763 N
Pressure is defined as the thrust acting per unit area. Its SI unit is Pascal.
Pressure = force / Area
Area, A = πr² = 3.14 x 0.491 x 10^-3 x 0.491 x 10^-3 = 7.57 x 10^-7 m^2
Pressure
[tex]P = \frac{0.763}{7.57 \times 10^{-7}}[/tex]
P = 1 x 10^6 Pascal
Thus, the pressure inside the pot is 10^6 Pa.
