Answer:
g / 16
Explanation:
T = 2π [tex]\sqrt{\frac{l}{g} }[/tex]
angular frequency ω = 2π /T
= [tex]\sqrt{\frac{g}{l} }[/tex]
ω₁ /ω₂ = [tex]\sqrt{\frac{g_1}{g_2} }[/tex]
Putting the values
ω₁ = ω , ω₂ = ω / 4
ω₁ /ω₂ = 4
4 = [tex]\sqrt{\frac{g}{g_2} }[/tex]
g₂ = g / 16
option d is correct.
