A random sample of n = 64 observations has a mean x = 29.9 and a standard deviation s = 3.7.

(a) Give the point estimate of the population mean μ. Find the 95% margin of error for your estimate. (Round your answer to four decimal places.)
(b) Find a 90% confidence interval for μ. (Round your answers to three decimal places.)

Respuesta :

Answer:

(29.128,30.672)

Step-by-step explanation:

Given that a random sample of n = 64 observations has a mean x = 29.9 and a standard deviation s = 3.7.

a) the point estimate of the population mean μ.

= Sample mean = 29.9

For 90% we use t critical value since population standard deviation is not known.

T critical for 90% is 1.669

Margin of error = ±[tex]1.669*\sqrt{\frac{3.7}{\sqrt{64} } } \\=0.7719[/tex]

b) Confidence interval 90%

= Mean±Marginof error

= [tex](29.128,30.672)[/tex]