Answer:
b. E = 2,28V
Explanation:
The maximum work is the same than ΔG. As ΔG could be written as:
ΔG = nFE (1)
Where n is moles of electrons transferred, F is faraday constant (96485 J/Vmol) and E is the voltage of the cell.
For the reaction:
CH₃OH(l) + ³/₂O₂(g) → CO₂(g) + 2H₂O(l)
The oxidation state of C in CH₃OH is -2 but in CO₂ is +4, that means transferred electrons are +4 - -2 = 6e⁻
Replacing in (1):
1320x10³ J = 6mol e⁻×96485J/Vmol×E
E = 2,28V
I hope it helps!
