Respuesta :
Answer:
[tex]S=5.6\times 10^{-9}\ M[/tex]
Explanation:
[tex]Mg(OH)_2[/tex] will form its respective ions in the solution as:
Consider the ICE take for [tex]Mg(OH)_2[/tex] as:
Mg(OH)₂ ⇄ Mg²⁺ + 2OH⁻
At t =equilibrium S 2S
Where, S is the molar solubility
The expression for Solubility product of [tex]Mg(OH)_2[/tex] is:
[tex]K_{sp}=[Mg^{2+}][OH^-]^2[/tex]
Given that:
pH = 12.50
Also, pH + pOH = 14
So, pOH = 14 - 12.50 = 1.5
[tex]pOH=-log(OH^-)[/tex]
[tex][OH^-]=10^{(-1.5)}=0.03162[/tex]
So, Total [OH⁻ ] = S + 0.03162
[tex]K_{sp}=5.6\times 10^{-12}[/tex]
So,
[tex]5.6\times 10^{-12}=S\times {(S + 0.03162)}^2[/tex]
Since, S is very small, So, S + 0.03162 ≅ 0.03162
Thus,
[tex]5.6\times \:10^{-12}=S\times \left(\:0.03162\right)^2[/tex]
[tex]S=\frac{5.6}{10^{12}\times \:0.0009998244}[/tex]
[tex]S=5.6\times 10^{-9}\ M[/tex]
The molar solubility of [tex]Mg(OH)_2[/tex] in a basic solution with a pH of 12.50 is:- [tex]5.6\times 10^{-9}\ M[/tex]
The study of chemicals is called chemistry. The ions only form in an ionic compound. The ionic compound is the strongest compound.
The correct answer is [tex]5.6*10^{-9}[/tex].
The ions of magnesium hydroxide are as follows:-
- Cation -[tex]mg^{2+}[/tex]
- Anion - OH-
What is equilibrium constant?
- The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium.
- A state approached by a dynamic chemical system after sufficient time has elapsed at which its composition has no measurable tendency towards further change
The formula used to solve the question is as follows:-[tex]Ksp = [Mg{^2+}][OH]^{2}[/tex]
The data is given as follows:-
pH = 12.50 pH + pOH = 14
hence, pOH = 14 - 12.50 = 1.5
so,
[tex]5.6*10^{-12} \\= S+ (0.3162)^2\\\\S \\=\frac{5.6}{10^{12}*0.0009998244}[/tex]
After solving the equation, the correct answer is [tex]5.6*10^{-9}[/tex]
For more information about the equilibrium constant, refer to the link:-https://brainly.com/question/17960050
