Answer:
.487 s⁻¹
Explanation:
Let damping constant be τ . The equation of decreasing amplitude can be written as
A = A₀ [tex]e^{-\tau t[/tex]
A / A₀ = [tex]e^{-\tau t[/tex]
At t = 9.43 s , A / A₀ = .01
.01 = [tex][e^{-\tau\times9.43[/tex]
ln.01 = - 9.43 τ
-4.6 = -9.43τ
τ = .487 s⁻¹
Answer:
0.05508 kg/sec
Explanation:
mass of the oscillator m= 0.231 Kg
amplitude of oscillation given by
[tex]A=A_0e^{-It}[/tex]
Ao= maximum amplitude
t= time and 1.00% of its initial value in t= 9.43 s.
A= 0.01Ao
⇒0.01=e^(-I×9.43)
ln100= 9.43×l
l=0.4883
we know that l= c/2m
c= damping constant
c= 2ml
=2×0.231×0.4883
=0.05508 kg/sec
