Respuesta :
Answer:
0.47 m
Explanation:
[tex]N[/tex] = Number of vibrations = 37
[tex]t[/tex] = total time taken = 33 s
[tex]T[/tex] = time period of each vibration
frequency of vibration is given as
[tex]f = \frac{N}{t} \\f = \frac{37}{33} \\f = 1.12[/tex] Hz
[tex]d[/tex] = distance traveled along the rope = 421 cm = 4.21 m
[tex]t[/tex] = time taken to travel the distance = 8 s
[tex]v[/tex] = speed of the wave
Speed of the wave is given as
[tex]v = \frac{d}{t}\\v = \frac{4.21}{8}\\v = 0.53 ms^{-1}[/tex]
[tex]\lambda[/tex] = wavelength of the harmonic wave
wavelength of the harmonic wave is given as
[tex]\lambda = \frac{v}{f} \\\lambda = \frac{0.53}{1.12} \\\lambda = 0.47 m[/tex]
Answer:
0.472 m
Explanation:
f = cycles/ second = 33 / 37 = 0.892 Hz
Vmean = Δx / Δt = 4.21m / 8s = 0.526
Vwave = λ x f
⇒ λ = f / Vwave = 0.526 / 0.892 = 0.472 m
