Answer:
There is enough evidence to support the attorney’s claim
Step-by-step explanation:
Given that one attorney claims that more than 25% of all the lawyers in Boston advertise for their business.
Sample size n =200
Sample proportion = [tex]63/200=0.315[/tex]
Hypotheses:
[tex]H_0: p=0.25\\H_a: p>0.25[/tex]
(right tailed testat 5% significance level)
Assuming H0 to be true, std error of p = [tex]\sqrt{0.25*0.75/200 \\=0.0306[/tex]
Test statistic z = p diff/std error
= [tex]\frac{0.315-0.25}{0.0306} \\=2.12[/tex]
p value for one tailed =0.0170
Since p <0.05 we reject null hypothesis
There is enough evidence to support the attorney’s claim
