Answer:
v = 2,413 104 m / s
Explanation:
We can solve this exercise using the conservation of the moment. The system is formed by the satellite and the planet, so the forces in the collision are internal and the moment is preserved.
The data they give are the mass (m) and velocity (v₁) of Phobos and the mass (M) and velocity (v₂) of the planet
Initial moment before the collision, let's take as positive the direction in which the planet moves (Mars)
p₀ = m (-v₁) + M v₂
Final moment after the collision
[tex]p_{f}[/tex] = (m + M) v
p₀ = [tex]p_{f}[/tex]
m (-v1) + M v2 = (m + M) v
v = (-m v1 + M v2) / (m + M)
calculate
v = (-1.066 10 16 19222 + 6.39 10 23 24131) / (1.066 1016 + 6.39 1023)
v = (-2.049 10 20 + 15.4197 10 27) /6.39 1023)
v = 1.5419 1028 / 6.39 1023
v = 2,413 104 m / s
We see that the change in speed is imperceptible