Answer:
The diameter of the circular path decrease
Explanation:
The magnitude of the magnetic force exerted on the proton is given by:
[tex]F=qvB[/tex]
According to Newton's second law, this force is equal to the centripetal force. Therefore, we have:
[tex]F=F_c\\qvB=ma_c[/tex]
Recall that [tex]a_c=\frac{v^2}{r}[/tex]. Replacing and solving for B:
[tex]qvB=m\frac{v^2}{r}\\B=\frac{mv}{qr}[/tex]
Thus, the field stregth is inversely proportional to the radius of the path and since the radius is directly proportional to the diameter, if the field strength increases, the diameter decreases.
