Answer:
a) 750 N/m
b) 60 J
Explanation:
the elongation of the bowstring x = 0.4 m
force F on full elongation= 300 N
now we know that F=kx
⇒k= F/x
[tex]k= \frac{300}{0.4} = 750 N/m[/tex]
work done in pulling
W= [tex]\frac{1}{2}kx^2[/tex]
W= [tex]\frac{1}{2}750\times0.4^2[/tex]
W=60 J
