Answer:
Explanation:
Speed of wave v = 30 m /s
Time period T = 16 x 10⁻³ s
a )
At x = 0 , y = 2 cm so amplitude A = 2 cm
b ) At t = 0 , the particle is at the top and going down so
initial phase = π / 2
c ) Maximum transverse speed will be equal to ωA
where ω is angular velocity and A is amplitude
ω = 2π / T
= 2x 3.14 / 16 x 10⁻³
= 392.5 rad / s
A = 2 cm = 2 x 10⁻²
ωA
= 392.5 x 2 x 10⁻²
= 7.85 m/s
d )
wave equation
y = A sin ( ωt + kx + π / 2 )
y = 2 x 10⁻² cos ( 392.5 t + kx )
velocity = ω / k
k = ω / v
= 392.5 / 1.5
= 261.67
wave equation
y = 2 x 10⁻² cos ( 392.5 t + 261.67 x ) in metre.
