Answer:
V = 27.56 m/s
Explanation:
It is given that,
Mass of the car, [tex]m_1=960\ kg[/tex]
Initial speed of the car, [tex]u_1=30\ m/s[/tex]
Mass of the deer, [tex]m_2=150\ kg[/tex]
Initial speed of the deer, [tex]u_2=12\ m/s[/tex]
It is mentioned that after the hitting. the deer remains on the car. It is a case of inelastic collision. Let V is the speed of final speed of the deer and the car. Using the conservation of momentum to find it as :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]
[tex]V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}[/tex]
[tex]V=\dfrac{960\times 30+150\times 12}{(960+150)}[/tex]
V = 27.56 m/s
So, the final velocity of the deer and the car is 27.56 m/s.
