20 liters of an incompressible liquid exert a force of 50 N on the surface of the Moon (g = 1.67 m/s2). What force will 7.6 liters of the liquid exert on the surface of the Earth?

Respuesta :

Answer:

111.50 N

Explanation:

Volume on the moon = 20 L

Acceleration on the moon = g = 1.67 m/s2

Volume on Earth = 7.6 L

Acceleration on Earth = 9.8 m/s2

The force exerted by the liquid on the moon is given by:

[tex]F_m=m*a_{moon}\\m=\frac{50}{1.67} \\m=29.94 kg[/tex]

An incompressible liquid has a constant density:

[tex]\rho = \frac{m}{v} \\\rho = \frac{29.94}{20} \\\rho = 1.497\ kg/L[/tex]

The force exerted by 7.6 liters on Earth is:

[tex]F=\rho*V*a_{Earth}\\F=1.497*7.6*9.8\\F=111.50\ N[/tex]