Answer:
The amount of energy released from the combustion of cooking fat is 1.547 kJ/mL.
Explanation:
The balanced equation of the combustion of cooking fat :
[tex]C_{51}H_{88}O_6+70O_2\rightarrow 51CO_2+44H_2O,\Delta H^o=-1310 kJ/mol[/tex]
Energy released on combustion of 1 mole of fat = ΔH° = 1310 kJ/mol
Molar mass of fat , M= 796 g/mol
Energy released on combustion of 796 gram of fat: 1310 kJ/mol
Energy released on combustion of 1 gram of fat:
[tex]\frac{1310 kJ/mol}{796 g/mol}\times 1 g=1.646 kJ[/tex]
As we know that :
Mass = Density × Volume
Volume of 1 gram is :
[tex]V=\frac{1 g}{0.94 g/mL}=1.064 mL[/tex]
Energy released on combustion of 1.064 mL of fat= 1.646 kJ
Energy released on combustion of 1 mL of fat:
[tex]=\frac{1.646 kJ}{1.064 }=1.547 kJ[/tex]
The amount of energy released from the combustion of cooking fat is 1.547 kJ/mL.
