Answer
given,
mass of the skydiver = 75 Kg
mass of pet = 20 g
to find the terminal speed of both the sky diver and the mouse
Using terminal speed formula
[tex]v = \sqrt{\dfrac{4mg}{\rho\ A}}[/tex]
ρ is the density of the air
A is the area of mouse and skydiver
[tex]v = \sqrt{\dfrac{4\times 75 \9.8}{1.23\times A}}[/tex]
Assuming area of Skydiver = 0.72 m²
and Area of mouse will be equal to = 0.0021 m²
now,
[tex]v_{skydiver} = \sqrt{\dfrac{4\times 75\times 9.8}{1.2\times 0.72}}[/tex]
[tex]v_{skydiver} =\sqrt{3402.777}[/tex]
[tex]v_{skydiver} =58.33\ m/s[/tex]
[tex]v_{mouse} = \sqrt{\dfrac{4\times 0.02\times 9.8}{1.2\times 0.0021}}[/tex]
[tex]v_{mouse} =\sqrt{311.11}[/tex]
[tex]v_{mouse} =17.63\ m/s[/tex]
