simplifying [tex]\frac{\sqrt{4}}{\sqrt[3]{4}}[/tex] we get [tex]4^{\frac{1}{6}}[/tex]
Option B is correct.
Step-by-step explanation:
We need to simplify: [tex]\frac{\sqrt{4}}{\sqrt[3]{4}}[/tex]
Solving:
[tex]\frac{\sqrt{4}}{\sqrt[3]{4}}[/tex]
We know that √ = 1/2 and ∛=1/3
[tex]\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}[/tex]
Applying exponent rule: [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
[tex]=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}[/tex]
So, simplifying [tex]\frac{\sqrt{4}}{\sqrt[3]{4}}[/tex] we get [tex]4^{\frac{1}{6}}[/tex]
Option B is correct.
Keywords: Solving Exponents
Learn more about Solving Exponents at:
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brainly.com/question/13174260
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