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Temperature is used to measure the output of a production process. When the process is in control, the mean of the process is and the standard deviation is . a. Construct an chart for this process if samples of size are to be used (to 2 decimals). b. Is the process in control for a sample providing the following data? (to 2 decimals) Conclude that the process in control. c. Is the process in control for the following data? (to 2 decimals) Conclude that the process in control.

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Answer:

Consider the following explanation

Standard deviation = .4

Mean = 128.5

Explanation:

a. given mean = 128.5 standard devaition s.d =0.4 n= sample size 6

UCL = mean +3 Q/ sqrt n = 128.5 + 3 * 0.4 /sqrt 6 = 128.9899

LCL = mean - 3   Q/ sqrt n = 128.5 - 3 * 0. 4/ sqrt 6 = 128.0101

A process is said to be out-of control, if any of sample points fall beyond the control limits (below the LCLor above the UCL)

b. Is the process in control for a sample providing the following data?

(128.8 +128.2 +129.11+ 28.7+ 128.4 +129.2 )/ 6 = 127.33

Since in the above sample, one point (129.2) is above the UCL and no point is below LCL (lessthan 127.3), the process is said to be out-of-control

x= 127.333

c. Is the process in control for a sample providing the following data?

(129.3 +128.7 +128.6 6 129.2 +129.5 + 129.0) / 6 =129.05

Since in the above sample, four points (129, 129.2, 129.3, 129.5) are above the UCL and nopoint is below LCL (less than 127.3), the process is said to be out-of-control

x= 129.05