A converging lens of focal length 20 cm is placed in contact with a diverging lens of focal length 30 cm. The focal length of this combination is

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Answer:

The focal lenth (F) =+10.0cm

Explanation:

The formular for combined focal length (F) is given as;

[tex]1/f = 1/f_{1} + 1/f_{2}[/tex]

In this  question,

F1 = 20cm

F2  = -30cm

Plugging the values into the formuar above,

[tex]1/f = 1/20 + 1/(-30)[/tex]

[tex]1/f = 0.05 - 0.033

[tex]1/f = -0.017

f = [tex]1/ -0.017[/tex]

f = 58.82cm

i.e. the combination behaves as a converging lens (because of the postive sign) of focal length 58.82cm .

This question involves the concepts of focal length and the combination of lenses.

The focal length of the given combination is "60 cm".

FOCAL LENGTH OF COMBINATION OF LENSES

The focal length of the combination of lenses is given by the following formula:

[tex]\frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2}[/tex]

where,

  • f = focal length of combination of lenses = ?
  • f₁ = focal length of first lens = 20 cm
  • f₂ = focal length of second lens = -30 cm (negtive sign for diverging lens

Therefore,

[tex]\frac{1}{f} = \frac{1}{20\ cm}-\frac{1}{30\ cm}\\\\[/tex]

f = 60 cm

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