Calculate the gravitational force between a baseball and earth. A baseball has a radius of 0.075 m and a mass of 0.145 kg. Earth has a mass of 5.9742•10^24 kg and a radius of 6.3710•10^6 m. Assume the baseball is resting on earths surface.

Respuesta :

Answer: 1.424 N

Explanation:

According to Newton's Universal Law of Gravitation:

[tex]F_{g}=G\frac{(m_{b})(m_{E})}{d^2}[/tex] (1)

Where:

[tex]F_{g}[/tex] is the gravitational force between the ball and Earth

[tex]G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex] the Universal Gravitational Constant

[tex]m_{b}=0.145 kg[/tex] is the mass of the ball

[tex]m_{E}=5.9742 (10)^{24} kg[/tex] is the mass of the Earth

[tex]d=r_{b}+r_{E}[/tex] is the distance between the ball and the Earth, being [tex]r_{b}=0.075 m[/tex] the radius of the ball and [tex]r_{E}=6.3710(10)^{6} m[/tex] the radius of the Earth

So, rewritting (1):

[tex]F_{g}=G\frac{(m_{b})(m_{E})}{(r_{b}+r_{E})^2}[/tex] (2)

[tex]F_{g}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(0.145 kg)(5.9742 (10)^{24} kg)}{(0.075 m+6.3710(10)^{6} m)^2}[/tex] (3)

Finally:

[tex]F_{g}=1.424 N[/tex] (4)