contestada

If you double a number and then add 40, you get 2/11 of the original number. What is the original number?

Respuesta :

Answer:

Let the number be n.

2n + 40= 2/11 n

multiplying the equation by 11,

22n + 440= 2n

20n+ 440=0

20n = -440

dividing both sides by 20,

n= -22

The original number would be -22.

The computation of the original number

Let the original number be x, the equation would be

[tex]2n + 40=\frac{2}{11}x[/tex]

Now, let multiply the equation by 11.

[tex]22n + 440= 2x\\20x=-440[/tex]

Finally, divide both sides with 20.

[tex]\frac{20x}{20} \\=\frac{-440}{20}[/tex]

Hence, the value of x would be derived as -22.

Learn more about algebraic equations here:

https://brainly.com/question/2241589