A waitress sold 12 ribeye steak dinners and 39 grilled salmon totaling $575.53 on a particular day. Another day she sold 25 ribeye steak dinners and 13 grilled salmon dinners, totaling $582.43. How much did each type of dinner cost?

Respuesta :

Answer:

cost of ribeye steak dinners = $10.36

cost of grilled salmon= $11.581

Step-by-step explanation:

Let the cost of one steak dinners be x

Let the cost of one  grilled salmon be y

One a particular day the waitress sells  12 ribeye steak dinners and 39 grilled salmon for a total is $575.53 which can be written in equation as

12(x)+39(y)= $575.53-------------------------------------(1)

On another day she sells  25 ribeye steak dinners and 13 grilled salmon dinners  totals to $582.43.This can be represented  as

25(x)+ 13(y)= $582.43-------------------------------------(2)

solving the equation (1) and (2)

eq(1) x 1[tex]12x+39y= 575.53[/tex]

eq(2) x 3[tex]125x+ 39y= 1747.29[/tex]-------------------------(3)

Subtracting these equation we get,

[tex]113x=1171.76[/tex]

[tex]x=\frac{1171.76}{113}[/tex]

x= 10.36

Now  substituting this in equation (1)

[tex]12(10.36)+39(y)= $575.53[/tex]

[tex]123.84+39y=575.53[/tex]

[tex]39y=575.53 - 123.84[/tex]

[tex]y=\frac{451.69}{39}[/tex]

y=11.581